If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2+5x-12=-6
We move all terms to the left:
x^2+5x-12-(-6)=0
We add all the numbers together, and all the variables
x^2+5x-6=0
a = 1; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·1·(-6)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-7}{2*1}=\frac{-12}{2} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+7}{2*1}=\frac{2}{2} =1 $
| x^2+5x-12=-36 | | 8/x-5=17/x | | 20.4=3.4m | | 15=r+12 | | 3x=180-6x | | -3+5+6+g=11-3g | | 15*x=0.50 | | p/(-2-(-6))=-12 | | 56=2g | | -3+5+6+g=-3g | | 3(7-2)=-3(5-n) | | w-3.8=9 | | 1.86x=12.462 | | 1,498+x=6,240 | | 4v=–20 | | 9.5+b=13.1 | | 55.46+x=62.42 | | n^2-4=68 | | 6.4x-12=14+3.8x | | c=3(11.47)-27 | | 10=s-6 | | 1/21+x=1/7 | | 20-5/3d=26 | | 3.5-7x=24.5 | | m+1/38=5 | | 4=36,mm=4,6,8,9 | | 9(x-)=-108 | | 4/7=27/h | | -11.6=m+11.7/0.5 | | -9x-7+10x=-7+6x | | 6^(2x-3)=4^*x-2) | | 57=3+p |